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Help !!!!!!!!!!!!!!!!

Help !!!!!!!!!!!!!!!!-example-1
User Integer
by
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2 Answers

3 votes

Answer:

Hey there!

5(v+3)-10v>-10

5v+15-10v>-10

-5v+15>-10

-5v>-25

v<5

Let me know if this helps :)

User Sutra
by
7.9k points
2 votes

Answer:


\Huge \boxed{v < 5}

Explanation:

5(v + 3) - 10v > -10

Expand brackets.

5v + 15 - 10v > -10

Combine like terms.

-5v + 15 > -10

Subtract 15 from both parts.

-5v > -25

Divide both parts by -5 (flip sign).

v < 5

User Lauri Oherd
by
7.2k points

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