117k views
0 votes
Find all values of $x$ such that $3x^2 + 16x + 5=0$. If you find more than one value, then list your solutions, separated by commas.

User Jeba
by
5.7k points

1 Answer

5 votes

answer

x = {-5, -⅓}

explanation


3 {x}^(2) + 16x + 5 = 0


3 {x}^(2) + 15x + x + 5 = 0


3x(x + 5) + 1(x + 5) = 0


(x + 5)(3x + 1) = 0


x = - 5 \: or \: - (1)/(3)


x = \{ - 5 \: , - (1)/(3) \}

HOPE IT HELPS...

BRAINLIEST PLEASE ;-)

User Vettiyanakan
by
5.9k points