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Find mKNLˆ. A. 264 B. 196 C. 247 D. 184

Find mKNLˆ. A. 264 B. 196 C. 247 D. 184-example-1
User Finesse
by
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1 Answer

4 votes

Answer:

A. 264

Explanation:

When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,

60° = 1/2[(18x - 6)° - (5x +17)°]

60° * 2 = (18x - 6 - 5x - 17)°

120° = (13x - 23)°

120 = 13x - 23

120 + 23 = 13x

143 = 13x

143/13 = x

11 = x

x = 11

(18x - 6)° = (18*11-6)°= (198 - 6)° = 192°

(5x +17)° = (5*11 +17)° =(55+17)° = 72°

m (arc KNL) = (18x - 6)° + (5x +17)° = 192° + 72°

m (arc KNL) = 264°

User Lammert
by
6.6k points
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