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In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

User Dangh
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1 Answer

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Answer: 6π

Explanation:

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.


A=\pi r^2\bigg((\theta)/(360^o)\bigg)

Given: r = 6, Ф = 60°


A=\pi (6)^2\bigg((60^o)/(360^o)\bigg)\\\\\\.\quad =\pi (6)^2\bigg((1)/(6)\bigg)\\\\\\.\quad =6\pi

User Suor
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