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\int\limits^4_3{x^(2)-x } \, dx help

1 Answer

2 votes

Answer:


(53)/(6)

Explanation:


\int\limits^4_3 {x^2-x} \, dx

= [
(x^3)/(3) -
(x^2)/(2) ] ← evaluate for upper limit - lower limit

= (
(64)/(3) -
(16)/(2) ) - (
(27)/(3) -
(9)/(2) )

=
(64)/(3) - 8 - 9 +
(9)/(2)

=
(155)/(6) - 17

=
(53)/(6)

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