Question

If the angles of a triangle are (2y - 5)degrees, (y + 20)degrees, and (3y-5) degrees what are the values of the angles​

Answer 1

51 2/3 , 48 1/3 and 80 degrees.

Explanation:

The 3 angles add up to 180 degrees.

2y - 5 + y + 20 + 3y - 5 = 180

6y + 10 = 180

6y = 180 - 10

6y = 170

y = 170 / 6 = 28 1/3 degrees.

So the 3 angles are 2(28 1/3) - 5, 28 1/3 + 20 and 3(28 1/3) - 5.

Answer 2

Explanation:

Let's solve:

As we know that the sum of angles of traingle adds to 180°

`\sf{2y - 5 + y + 20 + 3y - 5 = 180}`

Collect like terms

⇒
`\sf{6y - 5 + 20 - 5 = 180}`

⇒
`\sf{6y + 15 - 5 = 180}`

⇒
`\sf{6y + 10 = 180}`

Move constant to right hand side and change it's sign

⇒
`\sf{6y = 180 - 10}`

Calculate the difference

⇒
`\sf{6y = 170}`

Divide both sides of the equation by 6

⇒
`\sf{ (6y)/(6) = (170)/(6) }`

Calculate

⇒
`\sf{y = 28.34}`

Now, let's replace the value:

⇒
`\sf{2y - 5 = 2 * 28.34 - 5 = 51.68}`

⇒
`\sf{y + 20 = 28.34 + 20 = 48.34}`

⇒
`\sf{3y - 5 = 3 * 28.34 - 5 = 80.02}`

Hope I helped!

Best regards!!