Answer:
Please refer to the attached graph.
Slope = -3.125
Explanation:
Given
Time is placed on x axis.
Initially, height of rock climber is 25 feet above sea level.
![t_1 =0\ sec](https://img.qammunity.org/2021/formulas/mathematics/college/a98itv10b2j3l7gwhm16exdmbtgufh2nzn.png)
= 25 feet
After 8 seconds, he is at sea level.
![t_2 =8\ sec](https://img.qammunity.org/2021/formulas/mathematics/college/tx9xi4g7yfhsxkg24lh7fc8wtn0xsiavnc.png)
= 0 feet
To find:
Graph of the given points and Slope of the line depicted.
Solution:
Kindly refer to the attached graph.
Here, we have been given two points to be plotted on the xy coordinate plane.
1st point is (0, 25): Time is 0 and height above sea level is 25 ft
2nd point is (8, 0): Time is 8 seconds and height above sea level is 0 ft (i.e. he comes to sea level)
First of all, mark these points and join them with a straight line.
Please refer to attached graph.
Slope of a line is given as:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6g6za4c720e5154tr4m4qzakkci1x13a8r.png)
Here,
![y_2 = 0\\y_1 = 25\\x_2 = 8\\x_1 = 0](https://img.qammunity.org/2021/formulas/mathematics/college/fqnr32ls3oxf5jfji1419fg87v5kaclp19.png)
Using the formula:
![m=(0-25)/(8-0)\\\Rightarrow m=-(25)/(8) = \bold{-3.125}](https://img.qammunity.org/2021/formulas/mathematics/college/m6z8mvwmjkgdsi191y2311a6bz13gt14x6.png)