Question

Find the value of x Round to the nearest tenth

Pls help :(

Answer 1

Explanation:

Hey, there!!

Let's simply work with it,

Here,

In figure ABC,

let a= 14

b= 19

and c= 8.

Using cosine rule,

`{c}^(2) = {a}^(2) + {b}^(2) - 2ab.cosc`

putting value of all we get,

`{8}^(2) = {14}^(2) + {19}^(2) - 2 * 14 * 19 * cosx`

Now, simplifying them we get,

`64 = 196 + 361 - 532.cosx`

`532cosx = 557 - 64`

`or \: 532cosx = 493`

`or \: cosx = (493)/(532)`

cosx= 0.926691

Putting cos inverse,

`x = {cos}^( - 1) (0.926691)`

Therefore, x= 22.0752°

By rounding off we get,

x= 22° { as 0 is smaller than 5 itsvalue dont change}.

Hope it helps....