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Which of the following pairs of functions are inverses of each
other?

Which of the following pairs of functions are inverses of each other?-example-1
User Glh
by
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1 Answer

2 votes

Answer: C

Explanation:

For this problem, let's find the inverse for all f(x) and see which pairs with the g(x). To find the inverse, you replace the x with y and y with x. Then you solve for y.

A. Incorrect


y=(x-8)/(4) +9 [replace x with y and y with x]


x=(y-8)/(4) +9 [subtract both sides by 9]


x-9=(y-8)/(4) [multiply both sides by 4]


4(x-9)=y-8 [add both sides by 8]


4(x-9)+8=y

This does not match g(x), therefore, they are not inverses of each other.

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B. Incorrect


y=4(x-12)+2 [replace x with y and y with x]


x=4(y-12)+2 [subtract both sides by 2]


x-2=4(y-12) [divide both sides by 4]


(x-2)/(4) =y-12 [add both sides by 12]


(x-2)/(4) +12=y

This does not match g(x), therefore, they are not inverses of each other.

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C. Correct


y=3((x)/(2))-4 [replace x with y and y with x]


x=3((y)/(2) )-4 [add both sides by 4]


x+4=3((y)/(2) ) [divide both sides by 3]


(x+4)/(3) =(y)/(2) [multiply both sides by 2]


(2(x+4))/(3) =y

This matches g(x), therefore, they are inverses of each other.

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D. Incorrect


y=3((2)/(x) )-10 [replace x with y and y with x]


x=3((2)/(y) )-10 [add both sides by 10]


x+10=3((2)/(y) ) [divide both sides by 3]


(x+10)/(3) =(2)/(y) [multiply both sides by y]


(y)((x+10)/(3) )=2 [multiply both sides by
(3)/(x+10) or divide by
(x+10)/(3)]


y=(6)/(x+10)

This does not match g(x), therefore, they are not inverses of each other.

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After going through each problem, we found that the correct answer is C.

User Npdoty
by
4.5k points