Question

While in a stream 39 cm deep, they look down into the water and see a craw fish at the bottom. How deep does the stream appear to the student? (nwater = 1.33)

Answer 1

The depth of stream to the student is
`d_1 = 0.2932 \ m`

Step-by-step explanation:

From the question we are told that

The actual depth of the stream is
`d = 39 \ cm = 0.39 \ m`

The refractive index of the water is
`n = 1.33`

Generally the apparent depth of the stream is mathematically represented as

`d_1 = (d)/(1.33)`

substituting values

`d_1 = ( 0.39)/(1.33)`

`d_1 = 0.2932 \ m`