Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
![m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=(m_1u_1+m_2u_2)/((m_1+m_2))\\\\V=(100* 2.6+92* (-5))/((100+92))\\\\V=-1.04\ m/s](https://img.qammunity.org/2021/formulas/physics/college/xkh8iphh0p6dj0lkh337avn5x6szfz87w1.png)
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.