Question

The coil has a radius of 8 cm and 110 turns. While moving the magnet closer towards the coil, at a certain point in time, the voltage meter shows -310 mV. What is the magnitude of the rate of change of the flux through the coil?

Answer 1

The magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s

Step-by-step explanation:

Given;

radius of coil, r = 8 cm = 0.08 m

number of turns of the coil, N = 110 turns

the induced emf through the coil, E = -310mV

The induced emf through the coil is given by;

`E = - N(d \phi)/(dt) \\\\(d \phi)/(dt) = (E)/(-N)`

Where;

dФ/dt is the magnitude of the rate of change of the flux through the coil

`(d\phi)/(dt) = (-0.31)/(110) \\\\(d\phi)/(dt) =2.82*10^(-3) \ T.m^2/s`

Therefore, the magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s