Question

Light of wavelength 500 nm illuminates a round 0.50-mm-diameter hole. A screen is placed 6.0 m past the slit. What is the width of the central bright circle on the screen

Answer 1

14.64*10^-3 m

Step-by-step explanation:

given that

Length of the wavelength, λ = 500*10^-9 m

Diameter of the hole, D = 0.5 mm

length of the slit, L = 6 m

W = 2.44 λL / D, where

W = width of the screen in m

λ = wavelength of the light in nm

L = length of the slit in m

D = diameter of the hole in m

on substituting the values, we have

W = (2.44 * 500*10^-9 * 6) / 0.5*10^-3

W = 7.32*10^-6 / 0.5*10^-3

W = 0.01464 mm

or also, 14.64*10^-3 m