Answer:
350°C
Step-by-step explanation:
Heat gained by water and aluminum = heat lost by iron
q₁ + q₂ = -q
m₁C₁ΔT₁ + m₂C₂ΔT₂ = -mCΔT
(1 kg) (900 J/kg/°C) (50°C − 21°C) + (2 kg) (4186 J/kg/°C) (50°C − 21°C) = -(2 kg) (449 J/kg/°C) (50°C − T)
(900 J/°C) (29°C) + 2 (4186 J/°C) (29°C) = -2 (449 J/°C) (50°C − T)
26,100 J + 242,788 J = -44,900 J + 898 (J/°C) T
898 (J/°C) T = 313,788 J
T = 350°C