Question

3 of 3
Find the 10th term, T10, of the following sequence:
8,27,66, 131, 228,...

Answer 1

T10 = 1403.

Explanation:

8 27 66 131 228

Differences in terms are 19 39 65 97

20 26 32 <-------- increasing by 6

We can extend this to 19 39 65 97 135 179 229 285

20 26 32 38 44 50 56 62

347 415

68

So the 6th term is 228 + 135 = 363.

7th is 363 + 179 = 542

8th term = 542 + 229 = 771

9th term = 771 + 285 = 1056

10th term = 1056 + 347 = 1403.