Answer:
![\bold{(11)/(2 )}](https://img.qammunity.org/2021/formulas/mathematics/high-school/h7695ua3q3qu5dperr6lk1u7dpkc79ewrd.png)
Explanation:
Given the geometric series:
![\{\frac{1}2, -1, 2, -4, ..... \}](https://img.qammunity.org/2021/formulas/mathematics/high-school/l8s1y68iwabhbfovuem1m2sv5dpfplg3sc.png)
To find:
Sum of series upto 5 terms using the geometric series formula = ?
Solution:
Formula for sum of a n terms of a geometric series is given as:
![S_n=(a(1-r^n))/(1-r) \ \{r<1 \}](https://img.qammunity.org/2021/formulas/mathematics/high-school/qo0dxftpaoclrdb4mqubpq0xvvxbyfqyju.png)
is the first term of the geometric series
is the common ratio between each term (2nd term divided by 1st term or 3rd term divided by 2nd term ..... ).
Here:
![a = (1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/yb25fozofab7wcum74giypggsz2kyptvd6.png)
![r = (-1)/((1)/(2)) = -2](https://img.qammunity.org/2021/formulas/mathematics/high-school/101gohi8s38uhbm8g9neeg5qf8sjo9slek.png)
![n=5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cst4mnn2bni634cxl5ndw0lwh2ahv0w2h4.png)
So, applying the formula for given values:
![S_5=\frac{\frac{1}2(1-(-2)^5)}{1-(-2)} \\\Rightarrow S_5=(1-(-32))/(2 * 3) \\\Rightarrow S_5=(1+32)/(6) \\\Rightarrow S_5=(33)/(6) \\\Rightarrow \bold{S_5=(11)/(2)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/lzijpl3oz6tf78war2f6g0uoawbr0z80lk.png)
So, the answer is
![\bold{(11)/(2 )}](https://img.qammunity.org/2021/formulas/mathematics/high-school/h7695ua3q3qu5dperr6lk1u7dpkc79ewrd.png)