Question

For a body of Mass ‘m’ moving in a circle of radius ‘r’ if its velocity is halved, what will be the effect on the value of centripetal force?

Answer 1

Step-by-step explanation:

F = mv²/r

If the velocity is halved:

F' = m(v/2)²/r

F' = ¼ mv²/r

F' = ¼ F

The centripetal force is reduced by a factor of 4.