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Given f(x) = x^2 - 2x - 15 find the average rate of change over the interval [0, 5].

Given f(x) = x^2 - 2x - 15 find the average rate of change over the interval [0, 5].-example-1
User Ahrooran
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Answer:

Average Rate of Change : 3

Explanation:

" Remember that the average rate of change of function f say, on interval [a,b] would be f(b) - f(a) / b - a. Similarly we can solve for the average rate of this function. "

f(5) = x² - 2x - 15 = 5² - 2(5) - 15 = 25 - 10 - 15 = 0,

f(0) = 0² - 2(0) - 15 = 0 - 0 - 15 = - 15

And the average rate of change will be,

f(5) - f(0) / 5 - 0 = 0 - ( - 15 ) / 5 - 0

= 0 + 15 / 5 = 15 / 5 = 3

The average rate of change over the interval [0, 5] is hence 3.

User Skos
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