Question

Calculate the number of grams of deuterium in an 80,000-L swimming pool, given deuterium is 0.0150% of natural hydrogen

Answer 1

`m_(Deu)=2666.7g`

Step-by-step explanation:

Hello,

In this case, we can apply the following mole-mass-density relationship in order to compute the required grams of deuterium, considering that it is the 0.0150% (molar basis) of natural hydrogen (H₂):

`m_(Deu)=80000LH_2O*(1000gH_2O)/(1LH_2O)*(1molH_2O)/(18gH_2O) *(1molH_2)/(1molH_2O) *(2gH_2)/(1molH_2) *(2*0.0150g\ Deu)/(100gH_2) \\\\m_(Deu)=2666.7g`

Best regards.