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A giant armadillo moving northward with a constant acceleration covers the distance between two points 60 m apart in 6

seconds. Its velocity as it passes the second point is 15m/s.

1 Answer

2 votes

Answer:

a = 1.66 m /s²

Step-by-step explanation:

This is a kinematics exercise

v = v₀ + a t

x = v₀ t + ½ a t²

we solve for the initial velocity in the first equation and substitute in the second

v₀ = v - at

x = (v- at) t + ½ a t²

x = vt - a t² + ½ a t²

x = v t - ½ a t²

we seek acceleration

a = (v t -x) 2 / t²

let's calculate

a = (15 6 - 60) 2/6²

a = 1.66 m /s²

User Bhavik Ambani
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