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Verify the identity. ( 1-sin x)/cosx=cosx/(1+sin x)

User Pierre R
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3 votes

Answer:

See below.

Explanation:

I'm going to use what I assume is the correct question.


(1 - \sin x)/(\cos x) = (\cos x)/(1 + \sin x)


(\cos x)/(\cos x) * (1 - \sin x)/(\cos x) = (\cos x)/(1 + \sin x)


(\cos x(1 - \sin x))/(\cos^2 x) = (\cos x)/(1 + \sin x)

Now use the identity


sin^2 x + cos^2 x = 1


cos^2 x = 1 - sin^2 x

We replace
\cos^2 x in the left denominator.


(\cos x(1 - \sin x))/(1 - \sin^2 x) = (\cos x)/(1 + \sin x)

Factor the difference of squares in the left side denominator.


(\cos x(1 - \sin x))/((1 + \sin x)(1 - \sin x)) = (\cos x)/(1 + \sin x)


(\cos x)/(1 + \sin x) = (\cos x)/(1 + \sin x)

User Tanuj Yadav
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