Answer:
2500 J
Step-by-step explanation:
Q=(3/2)nRΔT
Q=(3/2)*2 mol*(8.314 J/mol*k)*100 k
Q=2494 J
6235.5J
Using ( nစ)p= ncp x change in temp
But cp= ( 1+ f/2)R
So cp= ( 1+ 3/2R
Cp= 5R/2
So = n x 5R/2x 150k
= 2 x 5/2x 8.314 x150
= 6235.5J
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