Ok so there are two ways to do this kind of pre-algebra.
I'm going to do it the way I learned it, and the way they teach you in schools.
Ok so you want the variables on one side and the constant term (normal numbers) on the other side (of the equation).
So to do that you have to bring the 6 to the right side.
17h=40+6
Except when you move it to the other side you have to change the sign in front of it.
+ → -
- → +
× → ÷
÷ → ×
In this case, there is an addition sign in front of the 6.
So + → - and the final equation is...
17h=40-6
If you want to do it the way they do it in schools, then you have to remove 6 from both sides (so it will still be equal).
17h+6=40
You have to subtract 6 from (17h+6), which would be 17h.
Then you have to subtract 6 from (40), which would be 40+(-6) or 40-6
The final equation is 17h=40-6
Ok so 40-6=34.
So 17h=34
Divide 34 by 17 or divide each side by 17.
h=34/17 or 2
♡ Hope this helped! ♡
❀ 0ranges ❀