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If a 2.2-kg ball is thrown with a velocity of 10m/s what is its KE​

2 Answers

3 votes

Answer:

110 joules

Explanation:


Mass = 2.2kg\\Velocity = 10m/s \\K.E = (1)/(2) mv^2\\K.E = (1)/(2) * 2.2 * 10^2\\K.E = (1)/(2) * 220\\K.E = (220)/(2) \\K.E = 110 joules

User Sergey Vidusov
by
8.7k points
1 vote

Answer:

The answer is 110 Joules

Explanation:

Kinetic energy ( KE) of an object is given by


KE = (1)/(2) m {v}^(2)

where

m is the mass

v is the velocity

From the question

m = 2.2 kg

v = 10 m/s

Substitute these values into the above formula

That's


KE = (1)/(2) * 2.2 * {10}^(2)


KE = 1.1 * 10

We have the final answer as

Kinetic energy = 110 Joules

Hope this helps you

User Prisan
by
8.0k points

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