Question

If a fish experiences an acceleration of 9.8 m/s^2 over a period of 1.4s (It must be falling), then what is its change in velocity?

Answer 1

The change in velocity for the fish experiencing an acceleration of 9.8 m/s² over a period of 1.4 seconds is 13.72 m/s.

Step-by-step explanation:

If a fish experiences an acceleration of 9.8 m/s² over a period of 1.4s, then the change in velocity can be calculated using the formula:

Change in velocity (\(\Delta v\)) = acceleration (a) × time (t)

So, \(\Delta v = 9.8 m/s² × 1.4 s = 13.72 m/s\). The fish's velocity will change by 13.72 m/s in the downward direction, assuming the acceleration due to gravity is 9.8 m/s² and there is no air resistance.