Question

What are the roots of the equation x ^2+ 6x + 8 = 0?

Answer 1

Hi there! :)

Answer:

`\huge\boxed{x = -4, -2}`

x² + 6x + 8 = 0

Factor the equation by finding two numbers that sum up to 6 and multiply into 8:

4 + 2 = 6

4 ×2 = 8

Rewrite in factored form:

(x + 4) (x + 2) = 0

Find the roots using the Zero-Product Property:

x + 4 = 0

x = - 4

x + 2 = 0

x = -2.

Therefore, the roots of this equation are at x = -4 and -2.