Question

Each of the sides of a square $S_1$ with area $16$ is bisected, and a smaller square $S_2$ is constructed using the bisection points as vertices. The same process is carried out on S_2 to construct an even smaller square $S_3$. What is the area of $S_3$?

Answer 1

hope this helps friend

Explanation:

A = a^2

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Answer 2

4 sq. units

Explanation:

Because the vertices of S₂ are the midpoints of S₁, the area of S₂ will be half of that of S₁ which is 16 / 2 = 8. Similarly, because the same process is carried out on S₂ to make S₃, the area of S₃ is 8 / 2 = 4 sq. units.