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A fire engine approaches a wall at 5 m/s while the siren emits a tone of 500 Hz frequency. At the time, the speed of sound in air is 340 m/s. How many beats per second do the people on the fire engine hear

User Viszman
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1 Answer

3 votes

Answer:

The values is
f_b =14.9 \ beats/s

Step-by-step explanation:

From the question we are told that

The speed of the fire engine is
v = 5\ m/s

The frequency of the tone is
f = 500 \ Hz

The speed of sound in air is
v_s = 340 \ m/s

The beat frequency is mathematically represented as


f_b = f_a - f

Where
f_a is the frequency of sound heard by the people in the fire engine and is is mathematically evaluated as


f_a = [(v_s + v )/(v_s -v) ]* f

substituting values


f_a = [(340 + 5 )/(340 -5) ]* 500


f_a = 514.9 \ Hz

Thus


f_b =514.9 - 500


f_b =14.9 \ beats/s

User Skilldrick
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