Answer:
The values is

Step-by-step explanation:
From the question we are told that
The speed of the fire engine is

The frequency of the tone is

The speed of sound in air is

The beat frequency is mathematically represented as

Where
is the frequency of sound heard by the people in the fire engine and is is mathematically evaluated as
![f_a = [(v_s + v )/(v_s -v) ]* f](https://img.qammunity.org/2021/formulas/physics/college/tgml6ftky4pujugo41sy6yhsnfgiqcqnvi.png)
substituting values
![f_a = [(340 + 5 )/(340 -5) ]* 500](https://img.qammunity.org/2021/formulas/physics/college/fyyrppdtkygdnibphphpzwsmt1zpa2bz29.png)

Thus

