Question

3. Calculate the amount of C2H5OH in moles present in 5.0 g of ethanol. Calculate the number of C atoms present in the same amount of glucose. g

Answer 1

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`n_(etOH)=0.11mol\ et OH`

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`atoms_C=1.0x10^(23) atoms\ C`

Step-by-step explanation:

Hello,

In this case, since ethanol has a molar mass of 46 g/mol, the moles in 5.0 g are:

`n_(etOH)=5.0g\ etOH*(1mol\ etOH)/(46 g\ etOH) =0.11mol\ et OH`

Moreover, since the formula of glucose is C₆H₁₂O₆, its molar mass is 180 g/mol and six moles of carbon are in one mole of glucose (based on carbon's subscript), the atoms are computed by using the 6:1 mole ratio and the Avogadro's number as shown below:

`atoms_C=5.0gC_6H_(12)O_6*(1molC_6H_(12)O_6)/(180gC_6H_(12)O_6)*(6molC)/(1molC_6H_(12)O_6) *(6.022x10^(23)atoms\ C)/(1molC) \\\\atoms_C=1.0x10^(23) atoms\ C`

Regards.