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PLEASE HELP!! Solve the triangle

PLEASE HELP!! Solve the triangle-example-1
User Sonstone
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1 Answer

3 votes

Answer:

Option D. m<A = 43, m<B = 55, a = 20

Explanation:

1. Determination of angle B.

Angle C = 82

Opposite C (c) = 29

Opposite B (b) = 24

Angle B =?

Using Sine rule, we can obtain the value of angle B as follow:

b/Sine B= c/Sine C

24/Sine B = 29/Sine 82

Cross multiply

29 × Sine B = 24 × Sine 82

Divide both side by 29

Sine B = (24 × Sine 82) /29

Sine B = 0.8195

Take the inverse of Sine.

B = Sine¯¹ (0.8195)

B = 55

2. Determination of angle A.

Angle C = 82

Angle B = 55

Angle A =?

The value of angle A can be obtained as follow:

A + B + C = 180 (sum of angle in a triangle)

A + 55 + 82 = 180

A + 137 = 180

Collect like terms

A = 180 – 137

A = 43

3. Determination of side a (Opposite A)

Angle C = 82

Opposite C (c) = 29

Angle A = 43

Opposite A (a) =?

The value 'a' can be obtained as by using sine rule as illustrated below:

a/Sine A = c/Sine C

a/Sine 43 = 29/Sine 82

Cross multiply

a × Sine 82 = 29 × Sine 43

Divide both side by Sine 82

a = (29 × Sine 43) /Sine 82

a = 20

Therefore,

m<A = 43, m<B = 55, a = 20

User Tyler Miller
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