Question

7) What is

the
solution
to a
system
with
equations
-3x-2y=-1
and
4x+6y=-12
?

Answer 1

x=3 y=-4

Explanation:

we try to first solve for x, so we need to cancel out the y. we can multiply the first equation by 3 to get -9x-6y=-3. Then we add -9x-6y=-3 with 4x+6y=-12. The -6y and 6y cancel each other out, so we are left with -5x=-15. That means x equals 3. Since we have found x, we can plug it back into any one of the equations to find y. So, -3(3)-2y=-1. -9-2y=-1 -2y=8 y=-4. We can check this by plugging it into the other equation too. 4(3) + 6y = -12. 12 + 6y=-12. 6y=-24. y=-4.