Help urgently wanted Find x

Question

asked Jul 9, 2021 23.7k views

1 Answer

Emile Zankoul · Answer 1 · 2021-07-16T01:43:02+0000

Answer:

Explanation:

$\sf{Given}$

$\sf{hypotenuse = 5}$

$\sf{base = 2.1}$

$\sf{perpendicular = x}$

Now, Let's find the value of x

Using Pythagoras theorem

$\sf{ {h}^(2) = {p}^(2) + {b}^(2) }$

Plug the values

⇒
$\sf{ {5}^(2) = {x}^(2) + {2.1}^(2) }$

Evaluate the power

⇒
$\sf{25 = {x}^(2) + 4.41}$

Swap the sides of the equation

⇒
$\sf{ {x}^(2) + 4.41 = 25}$

Move constant to R.H.S and change it's sign

⇒
$\sf{ {x}^(2) = 25 - 4.41}$

Calculate the difference

⇒
$\sf{ {x}^(2) = 20.59}$

Squaring on both sides

⇒
$\sf{x = 4.54}$

Hope I helped!

Best regards!!