Question

Help urgently wanted
Find x

Answer 1

`\boxed{ \bold{x = 4.54}}`

Explanation:

`\sf{Given}`

`\sf{hypotenuse = 5}`

`\sf{base = 2.1}`

`\sf{perpendicular = x}`

Now, Let's find the value of x

Using Pythagoras theorem

`\sf{ {h}^(2) = {p}^(2) + {b}^(2) }`

Plug the values

⇒
`\sf{ {5}^(2) = {x}^(2) + {2.1}^(2) }`

Evaluate the power

⇒
`\sf{25 = {x}^(2) + 4.41}`

Swap the sides of the equation

⇒
`\sf{ {x}^(2) + 4.41 = 25}`

Move constant to R.H.S and change it's sign

⇒
`\sf{ {x}^(2) = 25 - 4.41}`

Calculate the difference

⇒
`\sf{ {x}^(2) = 20.59}`

Squaring on both sides

⇒
`\sf{x = 4.54}`

Hope I helped!

Best regards!!