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A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)

2 Answers

5 votes

Answer:


\huge \boxed{\mathrm{0.0769 \ kg}}

Step-by-step explanation:


\displaystyle \sf Mass=(Potential \ energy)/(Acceleration \ of \ gravity * Height)


\displaystyle m=(PE)/(gh)


\mathrm{We \ need \ to \ find \ the \ mass.}


\displaystyle m=(20.8)/(9.8 * 27.6)


m= 0.0769

User Heff
by
4.8k points
2 votes

Answer:


\boxed{ \bold{ \purple{0.0769 \: kg \: }}}

Step-by-step explanation:


\sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}


\sf{distance \: = 27.6 \: metre}


\sf{mass = } ?


\sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^(2) }

Now, let's find the mass:


\sf{PE \: = mass * gravity \: * \: distance}

plug the values


\sf{20.8 = m * 9.8 * 27.6}

Multiply the numbers


\sf{20.8 = 270.48 \: m}

Swap the sides of the equation


\sf{270.48m = 20.8}

Divide both sides of the equation by 270.48


\sf{ (270.48m)/(270.48) = (20.8)/(270.48) }

Calculate


\sf{0.0769} kg

Hope I helped!

Best regards!!

User Chandrakant Sharma
by
5.2k points