Question

The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Answer 1

3.75m/s²

Step-by-step explanation:

g= GM/r²

For planet 1

`g_(1)`= GM/r² (i)

`g_(1)` = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

`g_(2)`= GM/(2r)²

`g_(2)`= GM/4r²

`g_(2)`= GM/r² *1/4

from (i)

`g_(2)`=
`g_(1)` *1/4

`g_(2)` = 15/4

`g_(2)` = 3.75m/s²