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What is the value of X

What is the value of X-example-1
User Mulhoon
by
9.4k points

2 Answers

3 votes

Answer:

∠JKL = 159

∠JKM = 43

∠MKL = 116

Explanation:

Step 1: Define a equation for the angles

∠JKL = ∠JKM +∠MKL

Step 2: Substitute the values in for the angles

(10x - 11) = (43) + (8x-20)

Step 3: Solve for x

10x - 11 = 43 + 8x - 20

2x = 34

x = 17

Step 4: Substitute x = 17 back into angle to solve

∠JKL = 10(17) - 11

=170 - 11

=159

∠JKM = 43

∠MKL = 8x - 20

= 8(17) - 20

= 136 - 20

=116

User Utopion
by
8.0k points
1 vote

Answer:

17=x

JKM =43

MKL = 116

JKL= 159

Explanation:

JKM + MKL = JKL

43+ 8x-20 = 10x-11

Combine like terms

23+8x = 10x-11

Subtract 8x from each side

23 +8x-8x = 10x-8x-11

23 = 2x-11

Add 11 to each side

23+11 = 2x-11+11

34 = 2x

Divide by 2

34/2 = x/2

17=x

JKM =43

MKL = 8x-20 = 8*17 -20 = 116

JKL= 10x-11 = 10*17 -11 = 159

User Christian Groleau
by
8.0k points

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