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Solve each equation 3x^2=80

1 Answer

6 votes

Answer:


x = (4√(15))/(3), x = (-4√(15))/(3)

or


x = (\pm4√(15))/(3)

Explanation:

Hello!

Use the quadratic formula:
x = (-b \pm √(b^2 - 4ac))/(2a)

First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0

3x² = 80

3x² - 80 = 0

Note, thats the value of b will be 0, as there is no "bx"

Now, solve:


  • x = (-(0) \pm √((0)^2 - 4(3)(-80)))/(2(3)) Plug in values

  • x = (\pm√(960))/(6) Simplify the radical (Discriminant)

  • x = (\pm8√(15))/(6) Pull out perfect squares

  • x = (4√(15))/(3), x = (-4√(15))/(3) Reduce factors

The solutions are
x = (4√(15))/(3), x = (-4√(15))/(3)

User Jay Zelos
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