Question

800 g of water and 160 g of alcohol are placed in a container. Knowing that the density of alcohol is 0.8 g / mL then the density (in g / mL) of the mixture obtained is:

Answer 1

0.96 g/mL

Step-by-step explanation:

The volume of 800 g of water is:

(800 g) / (1 g/mL) = 800 mL

The volume of 160 g of alcohol is:

(160 g) / (0.8 g/mL) = 200 mL

Density = mass / volume

ρ = (800 g + 160 g) / (800 mL + 200 mL)

ρ = 0.96 g/mL