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Suppose y varies jointly as x and z. Find y when x=5 and z=6, if y=144 when x=6 and z=10

User Gobot
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1 Answer

5 votes

Answer:

y=72

Explanation:

y varies jointly as x and z

y=k*x*z

Where,

k= constant of proportionality

y=144, x=6, z=10

y=k*x*z

144=k*6*10

144=60k

Divide both sides by 60

144/60=k

2 24/60=k

2 6/15=k

2 2/5=k

k=12/5

Find y when x=5 and z=6

y=k*x*z

y=12/5*5*6

=360/5

=72

y=72

User James Mallett
by
8.0k points

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