Answer:
1. Question for the investigation; Weather a heavy object falls faster than a light one
2. Both balls will fall at the same rate
3. The steps include showing that it takes equal time to fall from a given height
Step-by-step explanation:
1. Question for the investigation; Weather a heavy object falls faster than a light one
2. Both balls will fall at the same rate
3. The steps to prove that objects fall at the same are as follows;
a) Collect two small, dense objects of different mass such as two balls, a video camera, one ladder and a person to help
b) With the ladder and carrying with the two balls, climb to a reasonable height and while the video camera is running, drop the balls at the same time
c) Repeat the above step of dropping the balls from the same height three times and compare the footage on the video camera
It will be observed that the balls touch the ground at exactly the same time t, with the same velocity, v, from the height, s, given by the relation;
s = u·t + 1/2·g·t²
v = u + g×t
Where;
v = The velocity of the ball just before touching the ground
u = The initial velocity = 0 m/s
= The acceleration due to gravity = 9.81 m//s²
s = 0×t + 9.81×t²
t = √(s/9.81)
Therefore, the time in which the balls will touch the ground is a function of only the height and as the height is the same for both balls, the time it will take them to reach the ground will be the same.