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Using the Bohr model what is the radius of the electron orbit in the Hydrogen atom when the electron is in the n = 10 state?

User Gunstick
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1 Answer

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Answer:

r₁₀ = 52.9 nm

Step-by-step explanation:

In Bohr's model of the hydrogen atom, the radius of the orbitals can be written as a function of the radius of the first orbit

rₙ = n² a₀

where ao is 0.0529 nm and is the radius of the ground state of the atom

the radius for the excited state with n = 10

r₁₀= 10² a₀

r₁₀ = 100 a₀

r₁₀ = 52.9 nm

User Gilles Castel
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