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The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between and minutes. Find the probability that a randomly selected passenger has a waiting time minutes. 0 7 greater than 1.25

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Complete Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes.

Answer:

The probability is
P(X > 1.25) = 0.8214

Explanation:

From the question we are told that

The start time is a = 0 minutes

The end time is b = 7 minutes

Generally the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes is mathematically represented as


P(X > 1.25) = 1 - P(X \le 1.25)

=>
P(X > 1.25) = 1 - (1.25 - a)/( b- a )

=>
P(X > 1.25) = 1 -0.1786

=>
P(X > 1.25) = 0.8214

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