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If sin(x) = 3/5, what is sin(2x)

2 Answers

7 votes

Answer:

24/25

Step-by-step explanation:

Trig functions relate the angle of a triangle with the sides of that triangle (right triangle)

sin(x)= 3/5 (opposite/ hypotenuse) (25=9-x^2, using pythag. theorem, remaining side= 4)

now, cos(x)= 4/5

now, the double angle identity states:

sin2x= 2sinxcosx

so,

sin2x= 2 * (3/5) * (4/5) =

24/25

User PixelEinstein
by
5.2k points
6 votes

Answer: 24/25

====================================================

Step-by-step explanation:

If sin(x) = 3/5, then cos(x) = 4/5 through the use of the trig identity

sin^2(x) + cos^2(x) = 1

This is assuming that x is in quadrant Q1.

Plug those values into the identity below and simplify.

sin(2x) = 2*sin(x)*cos(x)

sin(2x) = 2*(3/5)*(4/5)

sin(2x) = 24/25

User LogicaLInsanity
by
4.4k points