Question

How does the energy stored in an isolated capacitor change if the potential difference is increased by a factor of six

Answer 1

Energy will be reduced by 0.3

Step-by-step explanation:

Given that E = 1/2 QV

So if V is increased by 6

=> V = E/ 3Q

So the energy will be divided by a factor 1/3 of be reduced by 0.3