Question

A constant current of 1.30 amps is passed through an electrolytic cell containing OsO2. How many hours will it take to produce 45.0 grams of osmium metal from this process

Answer 1

9.8 h

Step-by-step explanation:

From the question,

Os²⁻ - 2e⁻ = Os

From the equation above,

2 F of electron is needed to liberate 1 mole of osmium.

45 g of osmium contains 45/190 mole of osmium = 0.237 mole.

2 F ⇒ 1 mole.

2(0.237) F ⇒ 0.237 mole

0.474 F. will produce 45 g of osmium.

If 1 F = 96500 C ,

Then, 0.474 F = 45741 C,

But,

Q = it

t = Q/i....................... Equation 1

Given: Q = 45741 C, i = 1.30 A

Substitute into equation 1

t = 45741/1.3

t = 9.8 h.