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Mass on a Spring: A 0.150-kg air track cart is attached to an ideal spring with a force constant (spring constant) of 3.58 N/m and undergoes simple harmonic oscillations. What is the period of the oscillations

User Arjabbar
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1 Answer

4 votes

Answer:

The period is
T = 1.286 \ s

Step-by-step explanation:

From the question we are told that

The mass of the spring is
m = 0.150 \ kg

The spring constant is
k = 3.58 \ N/m

Generally the period is mathematically represented as


T = 2 \pi \sqrt{ (m)/(k) }

substituting values


T = 2 \pi \sqrt{ ( 0.150)/(3.58) }


T = 1.286 \ s

User Mark Hall
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