Question

g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a 40o angle (measured from vertical), he knows that he must release his spear at what angle

Answer 1

θ = 28.9

Step-by-step explanation:

For this exercise let's use the law of refraction

n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for air and index 2 for water where the fish is

sin θ₂ = n₁ / n₂ sin θ₁

in this case the air repair index is 1 and the water 1.33

we substitute

sin θ₂ = 1 / 1.33 sin t 40

sin θ = 0.4833

θ = sin⁻¹ 0.4833

θ = 28.9