Question

The expression 100 + 20m100+20m100, plus, 20, m gives the volume of water in Eduardo's pool (in liters) after Eduardo spends mmm minutes filling his pool. What is the volume of water in Eduardo's pool after he fills it for 5 \dfrac145 4 1 ​ 5, start fraction, 1, divided by, 4, end fraction minutes?

Answer 1

205 litres

Explanation:

Given:

Volume of water is given as:

`V=100+20m` (in litres)

m is the time in minutes spent filling water in Eduardo's pool.

To find:

Volume of water in the pool after the water is filled for
`5(1)/(4)` minutes.

Solution:

Here, volume of water in the Pool (in litres) is given by the equation:

`V=100+20m` ....... (1)

Where m is the time for which Eduardo fills the pool.

Here, we are also given that

m =
`5(1)/(4)` minutes =
`(5*4+1 )/(4)=(20+1)/(4)=(21)/(4)` minutes

And we have to find the value of V after
`(21)/(4)` minutes.

Let us put the value of m as
`(21)/(4)` minutes in the equation (1) to find the value of V.

`V=100+20m\\\Rightarrow V = 100 + 20 * (21)/(4)\\\Rightarrow V = 100+105\\\Rightarrow \bold{V = 205\ litres}`

So, the volume of water in the pool after
`(21)/(4)` minutes is 205 litres.