Question

How many solutions does the following equation have?

3(y+9)=12y+133(y+9)=12y+133, left parenthesis, y, plus, 9, right parenthesis, equals, 12, y, plus, 13
Choose 1 answer:
Choose 1 answer:

Answer 1

Hey There Answer One Solutions

Explanation:

Answer 2

One solution.

Explanation:

Given that the equation is:

`3(y+9)=12y+13`

To find:

The number of solutions of the given equation = ?

Solution:

First of all, let us learn a concept for number of solutions of a polynomial.

Number of solutions of a polynomial is equal to its degree.

Degree means the highest power of the variable.

Here, the variable is
`y` and it is observable that the highest power of

Therefore, only one solution will be there for the given equation.

Solving the equation:

`3(y+9)=12y+13\\\Rightarrow 3y+27=12y+13\\\Rightarrow 12y-3y=27-13\\\Rightarrow 9y =14\\\Rightarrow \bold{y = (14)/(9)}`

The one solution is
`\bold{y=(14)/(9)}`.

Hence, only one solution.