How many solutions does the following equation have? 3(y+9)=12y+133(y+9)=12y+133, left parenthesis, y, plus, 9, right parenthesis, equals, 12, y, plus, 13 Choose 1 answer: Choos…

Question

asked Feb 4, 2021 89.7k views

2 Answers

Christopherstyles · Answer 1 · 2021-02-08T20:35:56+0000

Answer:

One solution.

Explanation:

Given that the equation is:

3(y+9)=12y+13

To find:

The number of solutions of the given equation = ?

Solution:

First of all, let us learn a concept for number of solutions of a polynomial.

Number of solutions of a polynomial is equal to its degree.

Degree means the highest power of the variable.

Here, the variable is
and it is observable that the highest power of

Therefore, only one solution will be there for the given equation.

Solving the equation:

$3(y+9)=12y+13\\\Rightarrow 3y+27=12y+13\\\Rightarrow 12y-3y=27-13\\\Rightarrow 9y =14\\\Rightarrow \bold{y = (14)/(9)}$

The one solution is
$\bold{y=(14)/(9)}$ .

Hence, only one solution.