Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4)0=(3x+2)(x−4)0, equals, left parenthesis, 3, x, plus, 2, right parenthesis, left parenthesis, x, minus, 4, right parenthesis Erik said, “The right-hand side is factored, so I'll use the zero product property.” Caleb said, “I'll multiply (3x+2)(x-4)(3x+2)(x−4)left parenthesis, 3, x, plus, 2, right parenthesis, left parenthesis, x, minus, 4, right parenthesis and rewrite the equation as 0=3x^2-10x-80=3x 2 −10x−80, equals, 3, x, squared, minus, 10, x, minus, 8. Then I'll use the quadratic formula with a=3a=3a, equals, 3, b=-10b=−10b, equals, minus, 10, and c=-8c=−8c, equals, minus, 8." Whose solution strategy would work?