1 Answer

Martin Costello · Answer 1 · 2021-03-25T02:25:59+0000

Answer:

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=-1$ .

Explanation:

Consider the given limit problem is

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=?$

We need to find the value of given limit problem.

Taking limit, we get

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=(2(1)^2-9(1)+9)/((1)-3)$

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=(2-9+9)/(-2)$

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=(2)/(-2)$

$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=-1$

Therefore,
$\lim_(x\to 1)(2x^2-9x+9)/(x-3)=-1$ .

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